A sample of carbon dioxide gas at a pressure of 1.10 atm and a temperature of 20.6 C, occupies a volume of 19.2 L. If the gas is allowed to expand at a constant temperature to a volume of 24.3 L, the pressure of the gas sample will be atm.

P₂ = 0.87 atm

Explanation:

Given data:

Initial pressure = 1.10 atm

Initial volume = 19.2 L

Final volume = 24.3 L

Final pressure = ?

Solution:

The given problem will be solved through the Boyle's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

1.10 atm × 19.2 L = P₂ × 24.3 L

P₂ = 21.12 atm. L/ 24.3 L

P₂ = 0.87 atm

1. they vary with a higher number because boiling is way hotter than melting