What is the molecular formula of a compound that molecular mass of 54 g/mol and an empirical formula of C₂H₃? C₂H₃, C₄H₆, C₆H₉, C₈H₁₂

Molecular formula = C₄H₆

Explanation:

Given data:

Molecular mass of compound = 54 g/mol

Empirical formula = C₂H₃

Molecular formula = ?

Solution:

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula mass = 12×2 + 3×1 = 27 g/mol

n = 54 / 27

n = 2

Molecular formula = n (empirical formula)

Molecular  formula = 2(C₂H₃)

Molecular formula = C₄H₆

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