Can some please help me? 1) Balance the equation Fe2O3 + H2SO4 → Fe2(SO4)3 + H2O.
What is the mole ratio of H2SO4 and H2O in the equation?
1:3
3:2
2:1
3:3
2)Balance the equation Mg + Mn2O3 → MgO + Mn.
What is the mole ratio of Mg and Mn in the equation.
1:1
2:1
3:2
4;2

1. The mole ratio of H2SO4 and H2O in the equation = 3:3

2. The mole ratio of Mg and Mn in the equation = 3:2

Further explanation

Given

Reaction

1. Fe2O3 + H2SO4 → Fe2(SO4)3 + H2O

2. Mg + Mn2O3 → MgO + Mn.

Required

Balanced equation

Solution

1. Fe₂O₃ + H₂SO₄ → Fe₂(SO₄)₃ + H₂O

Give a coefficient

aFe₂O₃ + bH₂SO₄ → Fe₂(SO₄)₃ + cH₂O

Make an equation

Fe, left = 2a, right=2⇒2a=2⇒a=1

S, left=b, right=3⇒b=3

H, left = 2b, right = 2c⇒2b=2c⇒2.3=2c⇒c=3

The equation becomes :

Fe₂O₃ + 3H₂SO₄ → Fe₂(SO₄)₃ + 3H₂O

2. Mg + Mn₂O₃ → MgO + Mn.

Give a coefficient

aMg + Mn₂O₃ → bMgO + cMn.

Make an equation

Mn, left=2, right=c⇒c=2

O₂, left=3, right=b⇒b=3

Mg, left = a, right=b⇒a=b⇒a=3

The equation becomes :

3Mg + Mn₂O₃ → 3MgO + 2Mn.

For cyclohexane compounds drawn in a chair conformation:   -axial bonds are vertical  -equatorial bonds are parallel to two bonds within the ring.  thus, as i assume the chair conformation is drawn:   -the x group is in an axial position, as are the five other vertical bonds.  -three axial bonds are on the top face of the ring  -the other three axial bonds are on the bottom face  the position of the second substituent on each ring carbon is equatorial.  gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other.  drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1.  click this link and watch some academic videos that may you more understand the topic 

1. o2(g)as a product