What is the volume of C2H2 produced when 45g of water reacts completely with calcium carbide

The volume of C₂H₂ : 28 L

Given

45g of water

Required

The volume of C₂H₂

Solution

Reaction

CaC₂(s) + 2 H₂O(l) ⇒ C₂H₂(g) + Ca(OH)₂(aq)

mol of water (MW = 18 g/mol) :

mol = mass : MW

mol = 45 g : 18 g/mol

mol = 2.5

From equation, mol ratio H₂O : C₂H₂ = 2 : 1, so mol C₂H₂ :

= 0.5 x mol H₂O

= 0.5 x 2.5

= 1.25

The volume of C₂H₂(assume at STP, 1 mol = 22.4 L) :

=1.25 mol x 22.4 L

=28 L