If you mix aqueous solutions of potassium nitrate and iron(II)sulfate what will be the precipitate, if there is one at all?

No one will precipitated because these all are soluble in water

Explanation:

2KNO3 + FeSO4 > K2SO4 + Fe(NO3)2

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

it forms an anion that has a larger radius. anions have a negative charge and are larger than the original atom.