14. Consider the following balanced chemical equation:
P205
3 H2O → 2 H3PO4
Calculate the mass of hydrogen phosphate, H3PO, that will be produced from 105.9 g of P, Os.

Mass = 72.52 g

Explanation:

Given data:

Mass of hydrogen phosphate produced = ?

Mass of P₂O₅ react = 105.9 g

Solution:

Chemical equation:

P₂O₅ + 3H₂O     →     2H₃PO₄

Number of moles of P₂O₅:

Number of moles = mass/molar mass

Molar mass of P₂O₅ 283.9 g/mol

Number of moles = 105.9 g/ 283.9 g/mol

Number of moles = 0.37 mol

Now we will compare the moles of P₂O₅ with H₃PO₄ from balance chemical equation.

                     P₂O₅        :         H₃PO₄

                         1           :           2

                      0.37        :        2/1×0.37= 0.74 mol

Mass of H₃PO₄ :

Mass = number of moles × molar mass

Mass = 0.74 mol ×  98 g/mol

Mass = 72.52 g

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.