Calculate the percentage composition of Aluminum, Sulfur & Oxygen in the compound of Al(SO4)3

Percentage of O = 56.1 %

Percentage of Al =15.8%

Percentage of S = 28.1 %

Explanation:

Given compound Al₂(SO₄)₃

Molar mass of compound:

27×2 + 32×3 + 16×12 = 342 g/mol

Percentage of Al = ( Mass of Al / Total mass ) × 100

Percentage of Al = 54 /342 × 100

Percentage of Al =15.8%

Percentage of S = ( Mass of S / Total mass ) × 100

Percentage of S = 96 /342 × 100

Percentage of S = 28.1 %

Percentage of O = ( Mass of O / Total mass ) × 100

Percentage of O = 192 /342 × 100

Percentage of O = 56.1 %

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6

why is cellular respiration important for homeostasis?

it changes food into energy that the organism can use.

which of the following is most likely to happen if a cell is not able to divide?

the cell will not be replaced when it is damaged.

explanation: