For all seawater problems, assume the salinity is 3.5% If you have a 2000 gram sample of seawater, how many grams of pure water are there?
0.035 x 2000) = x, 2000 - x = pure water
Answer to the nearest WHOLE number.

1930g

Explanation:

We have been given that the salinity of sea water is 3.5%;

  Now the mass of sea water sample is 2000g

So, problem here is to find the quantity of pure water in the sample = ?

Solution:

Let us find the quantity of the salt in the sample;

       Salt content  = 3.5% x 2000  = 70g

Amount of pure water  = 2000 - 70 = 1930g

adding or remove a gaseous reactant or product changes the concentrations. if the concentration of reactant or product is increased, the system will shift away from the side in which concentration was increased (i.e. if the concentration of reactants is increased, the system will shift toward the products. if more products are added, the system will shift to form more reactants). conversely, if the concentration of reactant or product is decreased, the system will shift toward the side in which concentration was decreased (i.e. if reactants are removed, the system will shift to form more reactants. if the concentration of products is decreased, the equilibrium will shift toward the products).

explanation:

8 m/s because for him to get the same amount of energy as ray is putting out, bobby, who weighs half as much as ray, needs to run twice as fast.