The radius of a vanadium atom is 130 pm. How many vanadium atoms would have to be laid side by side to span a distance of 1.30 mm

5 000 000 (5 million atoms)

Explanation:

Let us assume that a vanadium atom has a spherical shape.

diameter of a sphere = 2 x radius of the sphere

Thus,

Radius of a vanadium atom = 130 pm

                                              = 130 x m

The diameter of a vanadium atom = 2 x radius

                                                         = 2 x 130 x

                                               = 260 x m

Given a distance of 1.30 mm = 1.30 x m,

The number of vanadium atoms required to span the distance =

                                                  = 5000000

Therefore, the number of vanadium atom that would span a distance of 1.30 mm is 5 million.

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