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Chemistry, 14.01.2021 16:40 HarryPotter10

CaCO3(s)+2H*(aq) →Ca2+ (aq)+H2001+CO262) Initial
Initial Concentration
Experiment
Massof CaCO3(s) (grams) of Haq) (M)
1
5.00
1.0
2
5.00
2.0
Initial Temperatureof
Reactants (°C)
25.0
25.0
The initial rate of formation of CO2(e) from the chemical reaction represented by the
equation above was studied in two separate experiments. The table above provides the
experimental conditions used. If both experiments are carried out with finely powdered
samples of the solid and 50.0mL of HCl(aq), which experiment, if any, will have the faster
initial rate of formation of CO2(g) and why?
The rate of formation of CO2(g) will be the same because the mass of CaCO3(s) and the volume of
HCl(aq) used will be the same in both experiments.
CO2(g) will be formed at a faster rate in experiment 2 because more H* particles can react per
unit time.
O CO26) will be formed at a faster rate in experiment 1 because the proportion of CaCO3(s)
particles to H* particles will be greater.
The rate of formation of CO2(e) will be the same because the surface area of the solid and the
average kinetic energy of the particles will be the same in both experiments.


CaCO3(s)+2H*(aq) →Ca2+ (aq)+H2001+CO262)

Initial
Initial Concentration
Experiment
Massof CaCO3(s)

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Answers: 3

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CaCO3(s)+2H*(aq) →Ca2+ (aq)+H2001+CO262) Initial
Initial Concentration
Experiment
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