What is the mass of 1.33 moles of Ba3(PO4)2? Choices:
108 g

801 g

659 g

801 mol

Please help :(

801 g

Explanation:

From the question given above, the following data were obtained:

Number of mole of Ba₃(PO₄)₂ = 1.33 moles

Mass of Ba₃(PO₄)₂ =?

Next, we shall determine the molar mass of Ba₃(PO₄)₂. This can be obtained as follow:

Molar mass of Ba₃(PO₄)₂ = (137.3×3) + 2[31 + (4×16)]

= 411.9 + 2[31 + 64]

= 411.9 + 2[95]

= 411.9 + 190

Molar mass of Ba₃(PO₄)₂ = 601.9 g/mol

Finally, we shall determine the mass of Ba₃(PO₄)₂. This can be obtained as follow:

Number of mole of Ba₃(PO₄)₂ = 1.33 moles

Molar mass of Ba₃(PO₄)₂ = 601.9 g/mol

Mass of Ba₃(PO₄)₂ =?

Mole = mass /Molar mass

1.33 = Mass of Ba₃(PO₄)₂ / 601.9

Cross multiply

Mass of Ba₃(PO₄)₂ = 1.33 × 601.9

Mass of Ba₃(PO₄)₂ = 801 g

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