FeCl3 + 3NaOH → Fe(OH)3 + 3NaCl How many grams of NaCl could you make with 2.43306 g of FeCl3?

g NaCl (use 5 sig figs

2.6299 g NaCl

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Stoichiometry

Step 1: Define

[RxN} FeCl₃ + 3NaOH → Fe(OH)₃ + 3NaCl

[Given] 2.43306 g FeCl₃

Step 2: Identify Conversions

[RxN] 1 mol FeCl₃ = 3 mol NaCl

Molar Mass of Fe - 55.85 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of Na - 22.99 g/mol

Molar Mass of FeCl₃ = 55.85 + 3(35.45) = 162.2 g/mol

Molar Mass of NaCl - 22.99 + 35.45 = 58.44 g/mol

Step 3: Stoichiometry

Step 4: Check

Follow sig fig rules and round. We need 5 sig figs (instructed).

2.62986 g NaCl ≈ 2.6299 g NaCl

c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current