Calculate the volume in liters of a 2.3*10^-6 mercury(I) chloride solution that contains of mercury(I) chloride . Round your answer to significant digits.

2.00x10⁵L

Explanation:

...That contains 125g of mercury(I) chloride...

The molarity, M, of a solution represents the moles of solute (Mercury(I) chloride), per liter of solution.

To solve this question, we need to determine the moles of mercury(I) chloride present in 125g. Then, with molarity, we can find the volume of the solution:

Moles Mercury(I) chloride -Molar mass: 271.52g/mol-:

125g * (1mol / 271.52g) = 0.460 moles

Volume:

0.460 moles * (1L / 2.3x10⁻⁶mol) =

5 structural isomers

the isomers are:

n-exane :   ch3ch2ch2ch2ch2ch3

2-methylpentane :   ch3ch(ch3)ch2ch2ch3

3-methylpentane :   ch3ch2ch(ch3)ch2ch3

2,3-dimethylbutane :   (ch3)2chch(ch3)2

2,2-dimethylbutane :   (ch3)3cch2ch3