Answer : 182 gexplanation :
the complete reaction for the formation of aluminum oxide is as follows;
4al + 3 > 2
so if the molar mass of the is 32.0 g/mol and
so, to form 3.80 mol of
(3.80 mol ) x (3 mol ) x (32.0 g )
dividing by 2 because two moles of will be formed;
∴ 364.8/2 = 182.4g