Gaseous ethane, C2H6, burns in the presence of oxygen gas according to the balanced equation below.
2 C2H6 (g) + 7 O2 (g) —+ 4CO2 (g) + 6 H20 (g)
How many moles of carbon dioxide can be produced from
1.00 mol of ethane?
04.00 mol CO2
0 0.50 mol CO2
01.00 mol CO2
2.00 mol CO2

Moles of Carbon dioxide(CO2) = 2

Given

Reaction

2 C2H6 (g) + 7 O2 (g) —+ 4CO2 (g) + 6 H20 (g)

Required

moles of carbon dioxide

Solution

The reaction coefficient shows the mole ratio of the compounds in the reaction equation (reactants and products)

From the equation, mol ratio of C2H6 : CO2 = 2 : 4, so mol CO2 :

mol CO2 = (4/2) x mol  C2H6

mol CO2 = 2 x 1

mol CO2 = 2

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.