A2.5l flask at 15°c contains a mixture of n2, he and ne at partial pressure of 0.32 atm for n2, 0.15 atm for he and 0.42 atm for ne. calculate the volume in liter at stp occupied by he and ne if the n2 is removed selectively. how to solve this problem?

The volume occupied at STP is 1.345 L

Explanation:

The equation given by ideal gas follows:

         .......(1)

where, P = pressure of the gas

V = Volume of the gas

T = Temperature of the gas

R = Gas constant =

n = number of moles of gas

We are given:

Putting values in equation 1, we get:

We are given:

Putting values in equation 1, we get:

STP conditions:

T = 273 K

P = 1 atm

Putting values in equation 1, we get:

Hence, the volume occupied at STP is 1.345 L

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