Show please the correct algorithm of doing the test. The solution reacts baseslly (OH) when:
a) c(H3O+) = 2.10^-8 mol. l
b) c(OH-) = 7.10^-10 mol. l
c) c(H3O+) = 1.10^-7 mol. l
d) c(H3O+) = 7.10^-1 mol. l
e) c(H3O+) = 1.10^-6 mol. l
f) c(OH-) = 1.10^-7 mol. l
g) c(OH-) = 7.10^-3 mol. l
h) c(H3O+) = 2.10^-12 mol. l

sorry don't know.

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :