How many moles of ammonia are in 0.175 L of 6.50 M aqueous ammonia solution? Find the numerical answer for this questions make sure to include the following : What is the chemical formula for ammonia? What is the formula for molarity ? When you give your numerical answer, what is the correct significant figures and how do you know that is the correct amount?

Moles of Ammonia (NH₃) in solution = 1.14

Given

0.175 L of 6.50 M aqueous ammonia

Required

moles of ammonia

Solution

Ammonia = NH₃

Molarity = moles of solute per liter of solution

n = M x V

n = 6.50 M x 0.175 L

n = 1.1375 moles

In a multiplication operation: the significant digits in the final product must follow the number of significant digits that are at least in the numbers involved in multiplying

6.50 = 3 sig fig

0.175 = 3 sig fig

So the result must be 3 sig fig

1.1375 rounded to 1.14

the law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products. because atoms are only rearranged in a chemical reaction, there must be the same number of sodium atoms and chlorine atoms in both the reactants and products