Suppose an AM talk radio station broadcasts radio waves with a frequency of 930. kHz. Calculate the wavelength of these radio waves. Round your answer to 3 significant digits.

323 m.

Explanation:

From the question given above, the following data were:

Frequency (f) = 930 KHz

Wavelength (λ) =?

Next, we shall convert 930 KHz to Hz. This can be obtained as follow:

1 KHz = 1000 Hz

Therefore,

930 KHz = 930 KHz × 1000 Hz / 1 KHz

930 KHz = 93×10⁴ Hz

Thus, 930 KHz is equivalent to 93×10⁴ Hz

Wavelength (λ) of a wave and the frequency (f) are related according to the equation:

Velocity = wavelength × frequency

v = λf

With the above formula, we can obtain the wavelength of radio wave as follow:

Frequency (f) = 93×10⁴ Hz

Velocity (v) of electromagnetic wave = 3×10⁸ m/s

Wavelength (λ) =?

v = λf

3×10⁸ = λ × 93×10⁴

Divide both side by 93×10⁴

λ = 3×10⁸ / 93×10⁴

λ = 323 m

Thus, the wavelength of the radio wave is 323 m

answer: a tank of height h is filled with water and sits on the ground. water squirts from a hole at a height y above the ground and has a range r. for two y values, 0 and h, r is zero. determine the value of y for which the range will be a maximum.

explanation:

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.