Hi, I am doing this question and needed help on how a ratio would be calculated to get the empirical formula. I keep getting an empirical formula of CH2, the mark scheme says C3H7.
I understand that to get C3H7, you have to multiply by 3 but I dont understand why
Here is the question:

Analysis of a different hydrocarbon Y shows that it contains 83.7% by mass of carbon.
Calculate the empirical formula of Y.
Use this empirical formula and the relative molecular mass of Y (Mr = 86.0) to
calculate the molecular formula of Y.

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Oxidation-reduction reactions (often called "redox" for short) are reactions that involve the transfer of electrons from one species to another. oxidation states, or oxidation numbers, allow chemists to keep track of these electron transfers. in general, one element will lose electrons (oxidation), with the result that it will increase in oxidation number, and another element will gain electrons (reduction), thereby decreasing in oxidation number. the species that is oxidized is called the reducing agent or reductant. the species that is reduced is called the oxidizing agent or oxidant. to sum up: oxidation = increase in oxidation state = loss of electrons = reducing agent reduction = decrease in oxidation state = gain of electrons = oxidizing agent part a which element is oxidized in this reaction? fe2o3+3co→2fe+3co2 enter the elemental symbol. view available hint(s) is oxidized part b which element is reduced in this reaction? 2hcl+2kmno4+3h2c2o4→6co2+2mno2+2kcl+4h2o enter the elemental symbol. view available hint(s) is reduced