How many oxygen molecules are produced when 89.5 g of mercury (II) oxide are allowed to decompose according to the following equation:
2HgO --> 2Hg + O,
2.48 x 1023 molecules
2.11 x 1023 molecules
1.24 x 1023 molecules
1.02 x 1023 molecules
6.02 x 1025 molecules

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally