Determine the empirical and molecular formula for chrysotile asbestos. Chrysotile has the following percent composition: 28.03% Mg, 21.60% Si, 1.16% H, and 49.21% O. The molar mass for chrysotile is 520.8 g/mol

The empirical and molecular formula : Mg₃Si₂H₂O₈ and Mg₆Si₄H₄O₁₆

Given

28.03% Mg, 21.60% Si, 1.16% H, and 49.21% O

Required

The empirical and molecular formula

Solution

Mol ratio : Mg : Si : H : O =

So empirical formula :

(Emprical formula)n=molecular formula

(Mg₃Si₂H₂O₈)n=520.8

(24.3+28.2+2.1+8.16)n=520.8

(258)n=520.8⇒n=2

The molecular formula : Mg₆Si₄H₄O₁₆

i would say b

explanation:

but i think i would need more information than that