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Formula of a copper (II)sulfate hydrate lab
Mass of empty dish: 50.58 g
mass of crystals and dish: 55.63
mass of crystals after first heating: 54.57
mass of crystals after second heating: 53.83
mass of crystals after 3rd heating: 53.74
then it asks for the mass of crystals in the evaporating dish. i said 50.58/55.63x100= 90.94(i’ve yet to round to significant figures) and i’m unsure as to whether or not this is the proper equation?? i get more questions on the crystals for the heating, and then it goes to ask: determine the mass of water evaporated from ye crystals during the heating. If you know what equation to use, please let me know!!
the other questions: using the mass of water evaporated from the crystals after the 3rd heating, determine the percentage by mass of water in the copper (II) sulfate hydrate crystals.
Based on the following formulae fir copper determine the GFM of the hydrate crystals: CuSO4 x 5H2O
then more like that but this ones for the accepted percentage by mass of water in the hydrate crystals: CuSO4x5H2O.
then determine percent error.
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Answers: 3
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Formula of a copper (II)sulfate hydrate lab
Mass of empty dish: 50.58 g
mass of crystals and...
mass of crystals and...
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