Identify the subatomic particles in strontium-82 and rubidium-82. Then, explain what type of nuclear decay is most likely to convert strontium-82 to rubidium-82.

Explanation:

The subatomic particles present in an atom are protons, neutrons and electrons. The protons of an atom can be determined by the "position" of the atom on the periodic table (since the periodic table is arranged according to the number of protons called atomic number). The atomic number (number of proton) of an atom can be assumed to be the number of electrons of a neutral atom since protons are positively charged and would require equal number of negative particles to balance it's charge to zero. The number of neutrons in an atom can be derived by subtracting the atomic number from the the mass number; this is because both the protons and neutrons constitute the mass of an atom.

From the above, we can deduce that strontium-82 (⁸²₃₈Sr) has 38 protons, 38 electrons and (82 - 38 = 44) 44 neutrons. While rubidium-82 (⁸²₃₇Rb) has 37 protons, 37 electrons and (82 -37 = 45) 45 neutrons.

The type of nuclear decay that would most likely convert strontium-82 to rubidium-82 is beta decay

⁸²₃₈Sr  ⇒   ⁸²₃₇Rb + °₊₁e

This type of beta decay is referred to as beta positive decay

the answer is the first option

explanation:

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