Consider the equations below. CH, (9) →C(s)+ 2H, (9) AH, – 74.6 kJ
C(s) + 2CI,(9)→ cCi, () AH, =-95.7 kJ
2H,(g) + 2CI,(9)→ 4HCI(G) AH, =-184.6 kJ
CH, (9) + 4Ca, (9) → Ca,(9) + 4HCI(9) AH, =-205.7 kJ
Complete the following based on the diagram.
Arrow A:
Arrow B:
Arrow C:
Arrow D:

just did the assignment and the answer was #1 +2 n

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

the term hydride is commonly named after binary compounds that hydrogen forms with other elements of the periodic table. hydride compounds in general form with almost any element, except a few noble gases. the trends and properties vary according to the type of intermolecular force that bonds the elements together, the temperature, its molecular masses, and other components. hydrides are classified into three major groups, depending on what elements the hydrogen bonds to. the three major groups are covalent, ionic, and metallic hydrides. formally, hydride is known as the negative ion of a hydrogen, h-, also called a hydride ion. because of this negative charge, hydrides have reducing, or basic properties. its special characteristics will be further discussed.

explanation:

it would only be the stuff in module eight so you need to study all the lessons in that you also could check the flvs

hope this : )