The atom of an element S has a mass number of 88 and contains in its nucleus 12 neutrons more than protons. What is the electronic structure: a) of the atom
b) The S2 + ion that it forms

Explanation:

Mass number = No of neutrons + no of protons

Let no of protons be p , No of neutrons = p + 12

Putting the given values

88 = p + 12 + p

76 = 2p

p = 38

n = 50

a ) Atom is Strontium ( Sr )

Electronic configuration

1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶5s²

b ) Sr²⁺

1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

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~ trueboss72