This table has information about the heat of fusion and the heat of vaporization of different substances. A 3-column table with 10 rows. Column 1 is labeled substance. Column 2 is labeled delta H fusion in kilojoules per mole. Column 3 is labeled delta H vaporization in kilojoules per mole. Ten rows are as follows: H 2 O, 6.01, 40.7. C O 2, 7.94, 25.2. O 2, 0.443, 6.81. N 2, 0.719, 5.58. F e, 14.9, 354. A l, 10.7, 255. C u, 13.0, 304. N a C l, 30.2, 171. C H 4, 0.936, 8.53. H 2 S, 2.37, 18.7. Which substance absorbs 58.16 kJ of energy when 3.11 mol vaporizes? Use q equals n delta H.. a. CH4 b. H2S c. CO2 d. NaCl

H₂S

Given

ΔH fusion and ΔH vaporization  of different substances

Required

The substance absorbs 58.16 kJ of energy when 3.11 mol vaporizes

Solution

We can use the formula :

Q=heat/energy absorbed

n = moles

The heat absorbed : 58.16 kJ

moles = 3.11

so ΔH vaporization :

The correct substance which has ΔH vaporization = 18.7 kj / mol is H₂S

(H₂S from the data above has ΔH fusion = 2.37 kj / mol and ΔH vaporization = 18.7 kj / mol)

personal, she chose to do it.

the best answer is d because the strong cohesion is caused by the ability of water molecules to undergo hydrogen bonding.

a is incorrect because when water solidifies, it becomes   ice, which expands and occupies a bigger volume for the same mass of water in its liquid state.

b is incorrect because water has high surface tension. besides bonding to itself it hydrogen bonds to other molecules at the top decreasing possibility for breaking of attractive forces.

c is incorrect because the water molecule has oxygen which is highly electronegative and so pulls the electron pair towards itself creating a dipole moment, making the molecule polar.

e is incorrect because water has strong adhesion, ability to stick to other molecules such as glass because of this molecules having stronger hydrogen bonding than water.