Describe how you would prepare 5.00 × 102 mL of a 1.75 M H2SO4 solution, starting with an 8.61 M stock solution of H2SO4

We prepare the volume of the 8.61 M stock solution of 0.102 L, then we dilute it by adding water to 0.5 L

Given

5.00 × 10² mL of a 1.75 M H₂SO₄ solution

8.61 M stock solution

Required

The volume of stock solution

Solution

Molarity from 8.61 M to 1.75 M ⇒Dilution

We can use dilution formula :

M₁=8.61 M

V₂=500 ml = 0.5 L

M₂=1.75 M

answer: at room temperature (roughly 20 degrees c), you can dissolve 203.9 grams (or 200 grams) of sugar in 100 ml of water. as water temperature increases, the amount of sugar that will dissolve increases, up to about 500 grams of sugar in 100 ml water at 100 degrees c.

explanation:

c. 75.7

i think that is the right