Which substance is the limiting reactant when 12 g of sulfur reacts with 18 g of oxygen and 24 g of sodium hydroxide according to the following chemical equation?

NaOH is the limiting reactant

Given

12 g of sulfur reacts with 18 g of oxygen and 24 g of sodium hydroxide

Required

The limiting reactant

Solution

Reaction

2 S(s) + 3 O₂(g) + 4 NaOH(aq) ⇒ 2 Na₂SO₄(aq) + 2 H₂O(l)

A method that can be used to find limiting reactants is to divide the number of moles of known substances by their respective coefficients, and the smallest ratio becomes a limiting reactant

S : O₂ : NaOH =

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