b. After 20,000 L of ethylene oxide at 748 kPa and 525 K is cooled to 293 K it is transferred to a 110,000 L tank. what is the new pressure?

75.9 KPa

Explanation:

From the question given above, the following data were obtained:

Initial volume (V1) 20000 L

Initial pressure (P1) = 748 kPa

Initial temperature (T1) = 525 K

New temperature (T2) = 293 K

New volume (V2) = 110000 L

New pressure (P2) =?

The new pressure pressure of the gas can be obtained by using the general gas formula as illustrated below:

P1V1 / T1 = P2V2 / T2

748 × 20000 / 525 = P2 × 110000 / 293

14960000 / 525 = P2 × 110000 / 293

Cross multiply

P2 × 110000 × 525 = 14960000 × 293

P2 × 57750000 = 4383280000

Divide both side by 57750000

P2 = 4383280000 / 57750000

P2 = 75.9 KPa

Thus, the new pressure of the gas is 75.9 KPa

water at room temperature is flowing through a pipe with pressure taps located 10 ft apart along one section of the pipe, which are connected to a mercury (s=13.6) manometer.