What mass of anhydrous copper (II) sulfate can be obtained by the heating of 125.00 grams of copper (II) sulfate pentahydrate?

79.91 g

Explanation:

First we calculate the number of moles of 125.00 grams of copper (II) sulfate pentahydrate (CuSO₄·5H₂O), using its molar mass:

In the reaction, CuSO₄·5H₂O turns into CuSO₄.

So now we convert 0.501 moles of CuSO₄ (anhydrous copper (II) sulfate) into grams, using the molar mass of CuSO₄:

answer: enthalpy

explanation:

for a exothermic reaction, the energy is released i.e. the energy of the products is lower than the energy of the reactants.

= enthaply

= energy of products

= energy of reactants

as , thus comes out to be negative. negative value of enthalpy shows that the reaction is exothermic.

it's filtration, but this is an assumption so my apologies if i got this