Write an equation including the pKa value that describes the reaction of acetic acid with aqueous NaOH.

CH₃COOH  +  NaOH → NaCH₃COO  +  H₂O

CH₃COO⁻  +  H₂O  ⇄   CH₃COOH  + OH⁻       pKa = 4.75

Explanation:

Acetic acid and NaOH make a neutralization reaction, where a salt and water are formed.

CH₃COOH  +  NaOH → NaCH₃COO  +  H₂O

Acetic acid gives protons to medium

NaOH gives hydroxides to medium

When we have protons and hydroxides, we can produce water. That's why it is a neutralization reaction.

The acid is weak, so the formed CH₃COO⁻ becomes in the conjugate strong base. This anion can make hydrolysis to water.

CH₃COO⁻  +  H₂O  ⇄   CH₃COOH  + OH⁻       pKa = 4.75

The NaOH is a strong base, so the Na⁺, as the conjugate weak acid, can't make hydrolysis.

We can't make this equilibrium.

Na⁺  +  H₂O ⇄  NaOH + H⁺           IMPOSSIBLE

the product of the pressure and volume is also constant

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