If I start with 25.0 grams of lead (II) nitrate and 15.0 grams of sodium iodide, what is the limiting reactant?

+

2

N

a

N

O

3

Moles of Lead(II) Nitrate =

m

a

s

s

/

m

o

l

a

r

m

a

s

s

= 25.0 grams//(207.20 xx 1 + 14.01 xx 2 + 16 xx 6

= 25.0 grams//331.22

= 0.075 moles

Moles of Sodium Iodide

= 15//(22.99+126.9)

= 15//149.89

= 0.100 Moles

Limiting Reagent in this case is Lead(II) Nitrate

Ratio of Moles of Lead Nitrate to Sodium Nitrate

1:2

Ratio of "moles" of lead nitrate to Sodium Nitrate

1

2

=

0.075

x

x

=

2

×

0.075

x

=

0.150

M

a

s

s

/

M

o

l

a

r

M

a

s

s

r

shield volcanos are angry and get mad over the smallest things so much that there heads erupt   pahoehoe and a'a lava. a composite volcano is the poller opposite of a shield volcano. its   peaceful thing and knows how to control its emotions.      

the answer is d.) potassium