If 100. mL of 0.100 M K2SO4 is added to 200. mL of 0.150 M KCl, what is the concentration of K + ions in the final solution? Assume that the volumes are additive.

The final concentration will be "0.167 M".

According to the question,

Moles of KCl,

Moles of K₂SO₄,

Total moles of K+ will be:

=

Total volume will be:

=

hence,

→ The final concentration of K+ will be:

=

=

=

=

Thus the above solution is correct.

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percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally