If 155 grams of potassium (k) reacts with 122 grams of potassium nitrate (kno3), what is the limiting reagent? 2kno3 + 10k 6k2o + n2

K = 39 g/mol
KNO3 = 101 g/mol

2 KNO3 + 10 K = 6 K2O + N2

2 x 101 g KNO3 10 x 39 g K
122 g KNO3 ??

122 x 10 x 39 / 2 x 101 =

47580 / 202 => 235.54 g  of K

 ( KNO3 is Excess reagent ) 

2 x 101 g KNO3 10 x 39 g K
??   155 g K

155 x 2 x 101 / 10 x 39 =

31310 / 390 => 80.28 g of KNO3   ( K is limiting reagent )

hope this helps!

Ch4 is nonpolar and insoluble in water. since all of the hydrogen atoms are evenly spread around the carbon atom even through the c h bond is polar all the poles cancel each other out.