You react 14.5 grams of sodium hydroxide with 14.5 grams of copper II sulfate. At the end of the lab you find that you recovered 7.99 grams of precipitate. When you write the balanced equation for you reaction, what is the coefficient in front of sodium hydroxide?

The coefficient  in front of sodium hydroxide is 2.

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

the balanced reaction between sodium hydroxide and copper (II) sulphate is :

Thus the coefficient  in front of sodium hydroxide is 2.

4d^55s^1 ( third choice)