Please answer Identify the element whose last electron would have the following four quantum numbers:
8. 3, 1,-1, +1/2
9. 4,2, +1, +1/2
10. 6, 1, 0, -1/2
11. 4,3, +3, -1/2
12. 2, 1, +1, -1/2
I

See Explanation

Explanation:

8.  3, 1, -1, +1/2 => 3pₓ¹ => Aluminum

9.  4, 2, +1, +1/2 => 4d₁¹ => Chromium

10. 6, 1, 0, -1/2 => 6p₀² => Argon

11.  4, 3, +3, -1/2 => 4f₊₃² => Lutetium

12. 2, 1, +1, -1/2  => 2p₊₁² => Neon

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.