Chemistry, 18.12.2020 07:00 fifthward92

Can u guys help on 22. It will only take a min.

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Answer from: martinezizzie

Alpha > beta>gamma

Explanation:

Comparing only the three common types of ionizing radiation, alpha particles have the greatest mass. Alpha particles have approximately four times the mass of a proton or neutron and approximately 8,000 times the mass of a beta particle.

Gamma radiation, unlike alpha or beta, does not consist of any particles, instead consisting of a photon of energy being emitted from an unstable nucleus. Having no mass or charge, gamma radiation can travel much farther through air than alpha or beta, losing (on average) half its energy for every 500 feet.

Answer from: xojade

$\boxed {\boxed {\sf Gamma, beta, alpha}}$

Explanation:

Alpha. beta, and gamma particles are all emitted from an unstable or radioactive nucleus during radioactive decay.

Alpha particles are essentially helium ions, made of 2 protons and 2 neutrons. It has an atomic mass of 4 atomic mass units.Beta particles are also known as electrons. They have masses of 1/1840 atomic mass units.Gamma particles are actually just rays or photons of electronegative energy emitted. They have no mass or a mass of 0 atomic mass units.

So, if we place the mass in increasing order (least to greatest), then it is gamma (0 amu), beta (1/1840 amu) and alpha (4 amu).

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

Answer from: Quest

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8

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