A mixture of 10.0 g of Ne and 10.0 g of Ar has a total pressure of 1.6 atm. Estimate the partial pressure of Ne in this mixture.

1.0atm is partial pressure of Ne

Explanation:

Partial pressure of a gas is mole fraction times total pressure. To find mole fraction of Ne we need to convert mass of Ne and Ar to moles using the molar mass of each atom and with the formula:

Mole fraction Ne = Moles Ne / (Moles Ne + Moles Ar)

We can solve for mole fraction of Ne and its partial pressure:

Moles Ne -molar mass: 20.1797g/mol-:

10.0g * (1mol / 20.1797g) = 0.496 moles of Ne

Moles Ar -Molar mass: 39.948g/mol-:

10.0g * (1mol / 39.948g) = 0.250 moles of Ar

Mole fraction of Ne:

0.496 moles Ne / (0.496moles + 0.250moles) = 0.665

Partial pressure Ne:

1.6atm * 0.665 =

the answer is b & c i believe : )