Given the following equation... Fe + H2SO4 → Fe2(SO4)3 + H2
What is the charge (oxidation number) of Fe in Fe2(SO4)3 in 334 g of Fe2(SO4)3 ? (use atomic masses rounded to the nearest whole number.)

The charge is +3

Explanation:

In Fe₂(SO₄)₃ the global charge is 0.

As we know, the sulfate ion, SO₄, has a charge of -2, as there are 3 SO₄ ions in the molecule, the global charge is -2*3 = -6. To solve for the charge of Fe we can use:

2Fe - 6 = 0

2Fe = +6

Fe = +3

- aluminum and copper chloride.

- the chloride ion to separate the aluminum from the oxygen so that the aluminum can react with the copper ions (and the water molecules).

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