A piston compresses the air in the cylinder by doing 61.0 J of work on the air. As a result, the air gives off 113.0 J of heat to the surroundings. If the system is the air in the cylinder, what is the change in its internal energy?

Explanation:

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In this case, since the first law of thermodynamics states that the heat added to system and the work done by the system are able to define the change in the internal energy as follows:

Since this problem shows that the system releases 113.0 J of heat, we use it negative as well as the 61.0 J of work performed on the system; therefore we write:

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answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

the awnser is group 12