The balanced equation for the syntheis of Iron (I) oxide is below: If 5.4 moles of Fe react with 4.7 moles of O2, what is the maximum amount of Fe2O3 (in moles) that can be produced? What is the limiting reactant?

a
3.1 moles of Fe2O3 is the maximum amount that can be produced. Oxygen is the limiting reactant.

b
2.7 moles of Fe2O3 is the maximum amount that can be produced. Iron is the limiting reactant.

c
7.1 moles of Fe2O3 is the maximum amount that can be produced. Oxygen is the limiting reactant.

d
10.8 moles of Fe2O3 is the maximum amount that can be produced. Iron is the limiting reactant.

Option B. 2.7 moles of Fe2O3 is the maximum amount that can be produced. Iron is the limiting reactant.

Explanation:

The balanced equation for the reaction is given below:

4Fe + 3O2 —> 2Fe2O3

From the balanced equation above,

4 moles of Fe reacted with 3 moles of O2 to produce 2 moles of Fe2O3.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

4 moles of Fe reacted with 3 moles of O2.

Therefore, 5.4 moles of Fe will react with = (5.4 × 3)/4 = 4.05 moles of O2.

Thus, we can see that only 4.05 moles out of 4.7 moles of O2 given is needed to react completely with 5.4 moles Fe. Therefore, Fe is the limiting reactant and O2 is the excess reactant.

Finally, we shall determine the maximum amount of Fe2O3 produced from the reaction.

In this case, the limiting reactant will be use because it will produce the maximum amount of Fe2O3 as all of it is used up in the reaction.

The limiting reactant is Fe and the maximum amount of Fe2O3 produced can be obtained as follow:

From the balanced equation above,

4 moles of Fe reacted to produce 2 moles of Fe2O3.

Therefore, 5.4 moles of Fe will react to produce = (5.4 × 2)/4 = 2.7 moles of Fe2O3.

Summary:

Limiting reactant => iron (Fe)

Maximum amount of Fe2O3 produce = 2.7 moles

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml