C3H5OH + 3 O2 --> CO2 + H2O When balancing the equation above, how many molecules of CO2 and H2O are produced? The first half is already balanced.

1.8069*10²⁴molecules of CO₂ and H₂O are produced.

Explanation:

C₃H₅OH + O₂ → CO₂ + H₂O

The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

Then, you must balance the chemical equation. For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts

Left side: 3 C, 6 H and 3 O.

Right side: 1 C, 2 H and 3 O.

The coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.

By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.  

So, balancing the C:

C₃H₅OH + O₂ → 3 CO₂ + H₂O

Then:

Left side: 3 C, 6 H and 3 O.

Right side: 3 C, 2 H and 7 O.

Now, balancing the H:

C₃H₅OH + O₂ → 3 CO₂ + 3 H₂O

Then:

Left side: 3 C, 6 H and 3 O.

Right side: 3 C, 6 H and 9 O.

Finally, balancing the O:

C₃H₅OH + 4 O₂ → 3 CO₂ + 3 H₂O

Then:

Left side: 3 C, 6 H and 9 O.

Right side: 3 C, 6 H and 9 O.

Since you have the same amount of each element on each side of the reaction, the reaction is balanced. Then 3 moles of CO₂ and 3 moles of H₂O are produced.

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole and it applies to any substance.

Then the following rule of three applies: if 1 mole contains 6.023*10²³ molecules, then 3 moles of CO₂ or 3 moles of H₂O, how many molecules does it contain?

amount of molecules= 1.8069*10²⁴

1.8069*10²⁴ molecules of CO₂ and H₂O are produced.

what is the question here. i think you messed up.

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally