) Calculate the Gibbs energy change for the formation of propane at 298K. Given that ∆H for propane is -103.85KJ/mol.∆S for the reaction is - 269.74KJ/mol.

ΔG = 80,278.67 J/mol

Explanation:

Given:

∆H = - 103.85KJ/mol

∆S = - 269.74KJ/mol

T= 298 K

The Gibbs energy change (ΔG) is calculated as follows:

ΔG = ΔH - TΔS

ΔG = (-103.85KJ/mol)-298K(- 269.74KJ/mol)

ΔG = (-103.85KJ/mol) - (-80,382.52 J/mol)

ΔG = 80,278.67 J/mol

the answer is c

tell me if wrong