Chemistry, 15.12.2020 16:50 sherry59Sherry59

Calculate the amounts of each substance in the reaction below if an initial amount of 0.400 moles are brought together with an initial amount of 2.29 moles of Cl2 in a 1.00 L vessel

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Answer from: esnyderquintero

Complete Question

Calculate the equilibrium amounts of each substance in the reaction below if an initial amount of 0.400 moles of CO are brought together with an initial amount of 2.20 moles of Cl2 in a 1.00 L vessel and then equilibrium is established at 900 K. Kc at this temperature = 0.800. COCl2(g)  CO(g) + Cl2(g)

The amount of each substance at equilibrium is

$[COCl_2 ] = 0.282 \ M$

$[CO] = 0.12 \ M$

$[Cl_2] = 2.008 \ M$

Explanation:

From the question we are told that

The initial amount of CO is n_1 = 0.400

The initial amount of Cl_2 is $n_2 = 2.20 \ moles$

The volume of the vessel is $V = 1.0 \ L$

The temperature is $T = 900 \ K$

The equilibrium constant at the given temperature is K_c = 0.800

The reaction is

$COCl_2 \underset{}{\stackrel{}{\rightleftharpoons}} CO + Cl_2$

Now Generating an I C E table

$COCl_2 \ \ \ \ \underset{}{\stackrel{}{\rightleftharpoons}} \ \ \ \ \ \ \ \ \ CO \ \ \ \ \ \ \ \ \ \ + \ \ \ \ Cl_2$

Initial [I] 0 0.400 2.20

Change [C ] + x -x - x

Equilibrium [E ] x 0.400- x 2.20 - x

Here x is the amount in terms of concentration by which COCl_2 and and Cl_2 decreased during the reaction

Generally the equilibrium constant is mathematically represented as

$K_c = \frac{[CO] [Cl_2]}{[COCl_2]}$

=> $0.800 = \frac{[0.400 - x] [2.20 - x ]}{[x]}$

=> 0.800 x = [0.400 - x ] * [ 2.20 - x ]

=> $x = 0.282 \ M$

Generally at equilibrium the amount of COCl_2 present is

$[COCl_2 ] = 0.282 \ M$

Generally the equilibrium the amount of present is

[CO] = 0.400 - 0.282

=> $[CO] = 0.12 \ M$

Generally the equilibrium the amount of Cl_2 present is

[Cl_2 ] = 2.29 - 0.282

=> $[Cl_2] = 2.008 \ M$

Answer from: Quest

This is what i found on google “when one phosphate group is removed by breaking a phosphoanhydride bond in a process called hydrolysis, energy is released, and atp is converted to adenosine diphosphate (adp). likewise, energy is also released when a phosphate is removed from adp to form adenosine monophosphate (amp).” i hope this you .

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the answer is barium and copper bromide

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