What is the resultant pressure if 1.7 mol of ideal gas at 273 K and 2.79 atm in a closed container of constant volume is heated to 315 K? Answer in units of atm.

The resultant pressure is 3.22 atm

Explanation:

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

    (At constant volume and number of moles)

where,

= initial pressure of gas  = 2.79 atm

= final pressure of gas  = ?

= initial temperature of gas  = 273K

= final temperature of gas = 315 K

Thus the resultant pressure is 3.22 atm

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