Calculate the moles of 336 L of carbon dioxide gas (CO2) at STP.

Explanation:

P

V

=

n

R

T

where:

P

=

pressure

V

=

volume

n

=

moles

R

=

universal constant

(

8.314

k

P

a

⋅

L

m

o

l

⋅

K

)

T

=

temperature (Kelvin)

Recall that at STP conditions:

P

=

101.325

k

P

a

T

=

273.15

K

To solve for the number of moles of carbon dioxide gas, substitute your known values into the ideal gas equation:

P

V

=

n

R

T

n

=

P

V

R

T

n

=

(

101.325

k

P

a

)

(

5.6

L

)

(

8.314

k

P

a

⋅

L

m

o

l

⋅

K

)

(

273.15

K

)

n

=

(

101.325

k

P

a

)

(

5.6

L

)

(

8.314

k

P

a

⋅

L

m

o

l

⋅

K

)

(

273.15

K

)

n

=

0.2498580892

m

o

l

n

=

0.25

m

o

l

(rounded to

2

significant figures)

201cm/s÷5: 18

explanation:

there is no explanation

there all right good

explanation: