determine the vapor pressure in atm of water in an aqueous solution of 12% BY MASS EHTYLEENE GLYCOL (ANITFREEZE) IF THE VAPOR PRESSURE OF

The given question is incomplete, the complete question is:

Determine the vapor pressure (in atm) of water in an aqueous solution of 12% by mass ethylene glycol (antifreeze) if the vapor pressure of pure water at that temperature is 0.095 atmospheres.

The correct answer is 0.091 atm.

Explanation:

Based on the given information, the mass of ethylene glycol is 12% by mass, which means 12 grams of ethylene glycol dissolved in 88 grams of water.

The moles of a substance can be determined by using the formula,

Moles = Weight/molecular mass

Number of moles of water = mass/molecular mass

= 88g/18g/mol

= 4.88 moles

Number of moles of ethylene glycol = Mass/molecular mass

= 12 grams/62g/mol

= 0.193 moles

Mole fraction of water will be,

Mole fraction = number of moles of water/Number of moles of water+Number of moles of ethylene glycol

Mole fraction = 4.88/4.88+0.193

= 0.961

Vapor pressure of water can be determined by using the formula,

Vapor pressure = Vapor pressure of pure water * Mole fraction of water

= 0.095 * 0.961

= 0.091 atm.

explanation:

venn diagram is pictorial representation with of circles showing the relation between two finite sets or things. the intersection part of two circles conveys the relation present in between those sets or things.

here in the venn diagram of sand and salt two circles represent sand and salt. but the area falling under the intersection of these circle represents the mixture of sand and salt.

so, in a venn diagram the mixture will be placed in a middle that is in between the intersection of two circles.

the answer is c

tell me if wrong