A 1.00 g sample ofNH4N03 is decomposed in a bomb calorimeter. The temperature increases by 6.12 oc. What is the molar heat of decomposition of NH4N0.1

This question is incomplete, the complete question is;

A 1.00 g sample of NH4NO3 is decomposedin a bomb calorimeter. The temperature increases by 6.12°C. What is the molar heat of decomposition for ammonium nitrate?

Molar mass, NH4NO3 80.0 g/mol

Calorimeter Constant   1.23 kJ/°C

the molar heat of decomposition for ammonium nitrate is - 602.4 kJ/mol

Explanation:

Given that;

change in temperature ΔT = 6.12 °C

Calorimeter Constant C = 1.23 kJ/°C

Molar mass, NH4NO3 = 80.0 g/mol

we know that;

Heat gained by the calorimeter (Q1) = Heat lost by the decomposition of NH4NO3 (Q2)

Q1 = C × ΔT

Q1 = (1.23 kJ/K) × (6.12 K) = 7.53 kJ

Q value we get becomes negative since we are talking about reaction and not calorimeter

hence

Q1 = - 7.53 kJ

now

1 g NH4NO3 decomposed, - 7.53 kJ of heat is released

so if 80 g which is 1 mol NH4NO3 decompose, the heat will be;

(80 g/mol x -7.53 kJ) / 1 g = - 602.4 kJ/mol

Therefore the molar heat of decomposition for ammonium nitrate is - 602.4 kJ/mol

where is the following

explanation: