My car has an internal volume of 3,600 L. If the sun heats my car from a temperature of 18.0 degrees Celsius to a temperature of 45.0 degrees Celsius, what will the pressure inside my car be? Assume the pressure a was initially 101.3 kPa.

110.7 kpa or 1.097 atm your choice of pressure units

Explanation:

We can assume the Volume is constant since we are not told other wise and it is indeed a car. We can Use P1/T1= P2/T2

So (T2xP1 )/ T1 = P2

(318Kx101.3kpa)/291k = 110.7 kpa or 1.097 atm your choice of pressure units

if your wondering why i used Kelvin gas laws are always in units of Kelvin

n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.

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the political sponsor of weights and measures reform in the french revolutionary national assembly was the bishop of autun, better known as talleyrand. under his auspices, the french academy appointed several committees to carry out the work of developing a usable system of weights and measures for france. one of the committees recommended a decimalized measurement system based upon a length equal to one ten-millionth of the length of a quadrant of the earth’s meridian (i.e., one ten-millionth of the distance between the equator and the north pole).